Roman Zeyde 5fbd7553ed interface: fix check_host_name() pattern matching ...

The existing pattern matching code:

    val.find('*.') == 0 and name.find(val[1:]) + len(val[1:]) == len(name)

will return True in the following case:

   val = '*.host.com'
   name = 'blah.org'

since string.find() will return -1, len(val[1:]) == 9 and len(name) == 8.

2015-07-26 18:11:30 +03:00

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